10.) Specify the electron-domain geometry for the following two species using the VSEPR model: XeCl_{4} and IO_{4}^{−}. For each species, predict the bond angles based on the electron-domain geometry.
(a) XeCl_{4}
geometry:
linear
trigonal planar
bent
tetrahedral
trigonal pyramidal
trigonal bipyramidal
seesaw
T-shaped
octahedral
square pyramidal
square planar
pentagonal bipyramidal
pentagonal pyramidal
pentagonal planar
bond angle:
60°
72°
90°
109.5°
120°
180°
(b) IO_{4}^{−}
geometry:
linear
trigonal planar
bent
tetrahedral
trigonal pyramidal
trigonal bipyramidal
seesaw
T-shaped
octahedral
square pyramidal
square planar
pentagonal bipyramidal
pentagonal pyramidal
pentagonal planar
bond angle:
60°
72°
90°
109.5°
120°
180°
Solution:-
XeCl4
Around the xenon atom, there are 4 bonding pairs, i.e. 4 Xe−Cl bonds, and 2 lone pairs on Xe. These are arranged in the shape of an octahedron, with the non-bonding electron pairs trans with respect to each other. Because we describe molecular geometry on the basis of actual atoms, the geometry of the XeCl4 molecule is square planar.
Bond Angle of XeCl4 = 90 Degree
IO_{4}^{−}
The geometry of IO4- is Tetrahedral.
And, The bond angle in a IO4- (Tetrahedral) is 109.5^{o}
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